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A `4 : 1` mixture of helium and methane contained in a vessel at 10 bar pressure. During a hole in the vessel, the gas mixture leaks out. The composition of the mixture effusing out initially isA. `8:1`B. `1:8`C. `1:4`D. `4:1` |
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Answer» Correct Answer - A Molar ratio of He and `CH_4=4:1` `:.` partial pressure `P_(He)=4/5xx20=16` bar partial pressure `P_(CH_4)=1/5xx20=4` `:. P_(He):P_(CH_4)=16:4` `because` time of diffusion is same base `r_(He)/r_(CH_4)=n_(He)/n_(CH_4)=p_(He)/p_(CH_4)xxsqrt(M_(CH_4)/M_(He))=16/4xxsqrt(16/4)=4xx2=8:1` |
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