1.

A 4:1 mixture of helium and methane is contained in a vessel at 10 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. The composition of the mixture effusing out initially is

Answer»

`8:1`
`8:3`
`4:1`
`1:1`

Solution :Pressure of helium=8 BAR
Pressure of `CH_(4)=2` bar
`(r_(He))/(r_(CH_(4)))=(P_(1))/(P_(2))sqrt((M_(CH_(4)))/(M_(He)))=(8)/(2)sqrt((16)/(2))=(8)/(1)=8:1`


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