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A 4:1 mixture of helium and methane is contained in a vessel at 10 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. The composition of the mixture effusing out initially is

Answer» <html><body><p>`8:1`<br/>`8:3`<br/>`4:1`<br/>`1:1`</p>Solution :Pressure of helium=8 <a href="https://interviewquestions.tuteehub.com/tag/bar-892478" style="font-weight:bold;" target="_blank" title="Click to know more about BAR">BAR</a> <br/> Pressure of `CH_(4)=<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` bar <br/> `(r_(He))/(r_(CH_(4)))=(P_(1))/(P_(2))sqrt((M_(CH_(4)))/(M_(He)))=(8)/(2)sqrt((16)/(2))=(8)/(1)=8:1`</body></html>


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