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A `4:1` mixture of helium and methane is contained in a vessel at 10 bar pressure. Due to a hole in the vessel, the gas mixture leaks out. The composition of the mixture effusing out initially isA. `8:1`B. `8:3`C. `4:1`D. `1:1` |
Answer» Correct Answer - A Pressure of helium=8 bar Pressure of `CH_(4)=2` bar `(r_(He))/(r_(CH_(4)))=(P_(1))/(P_(2))sqrt((M_(CH_(4)))/(M_(He)))=(8)/(2)sqrt((16)/(2))=(8)/(1)=8:1` |
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