A `4:1` molar mixture of `He` and `CH_(4)` is contained in a vessel at `20 bar` pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the composition of the mixture effusing out initially?

A `4:1` molar mixture of `He` and `CH_(4)` is contained in a vessel at

1.	A `4:1` molar mixture of `He` and `CH_(4)` is contained in a vessel at `20 bar` pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the composition of the mixture effusing out initially?
Answer» Pressure `=20 bar` Molar ratio `=4:1` (`He` and `CH_(4)`) `P_(He)=(4)/(5)xx20=16 bar` `P_(CH_(4))=(1)/(5)xx20=4 bar` `(r_(1))/(r_(2))=(P_(1))/(P_(2))xxsqrt((M_(2))/(M_(1)))` `(r_(He))/(r_(CH_(4)))=(P_(He))/(P_(CH_(4)))xxsqrt((M_(CH_(4)))/(M_(He)))=(16)/(4)xxsqrt((16)/(4))=8` Therefore, the ratio of moles of heilum and methane coming out initially is `8:1`.

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A `4:1` molar mixture of `He` and `CH_(4)` is contained in a vessel at `20 bar` pressure. Due to a hole in the vessel, the gas mixture leaks out. What is the composition of the mixture effusing out initially?

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