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A 40 Ω electric heater is connected to 200 V, 50 Hz main supply. The peak value of the electric current flowing in the circuit is approximately- (a) 2.5 A (b) 5 A (c) 7 A (d) 10 A |
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Answer» (c) 7 A l0 = \(\frac{V_0}{R}\)= \(\frac{200{\sqrt2}}{40}\) 5 √2 ≈ 7A |
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