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A 400 mg iron capsule contains 100 mg of ferrous fumarate, `(CHCOO)_(2)`Fe. The percentage of iron present in it is approximatelyA. `8*2`B. `25%`C. `16%`D. unpredictable |
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Answer» Correct Answer - A Mol. Mass of `Fe(CHCOO)_(2) = 170` Fe in 100 mg of `Fe(CHCOO)_(2) = (56xx100)/(170)` = 32.9 mg Total Fe in 400 mg of capsule = 32.9 mg `:.` percentage of Fe in capsule `= (32.9xx100)/(400) = 8.2` |
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