1.

A 400 mg iron capsule contains 100 mg of ferrous fumarate, `(CHCOO)_(2)`Fe. The percentage of iron present in it is approximatelyA. `8*2`B. `25%`C. `16%`D. unpredictable

Answer» Correct Answer - A
Mol. Mass of `Fe(CHCOO)_(2) = 170`
Fe in 100 mg of `Fe(CHCOO)_(2) = (56xx100)/(170)`
= 32.9 mg
Total Fe in 400 mg of capsule = 32.9 mg
`:.` percentage of Fe in capsule
`= (32.9xx100)/(400) = 8.2`


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