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A `5.0 cm^(3)` solution of `H_(2)O_(2)` liberates `1.27 g` of iodine from an acidified `KI` solution. The precentage strength of `H_(2)O_(2)` isA. `11.2`B. `5.6`C. `1.7`D. `3.4` |
Answer» Correct Answer - D `H_(2)O_(2)=KI=I_(2)` mEq of `H_(2)O_(2)=5xxN` mEq of `I_(2)=("Weight")/(EW)xx1000` `=1.27/127xx1000=10 mEq` `I_(2)=MW=254/2=127` `:.` mEq of `I_(2)` `5xxN=10 :. N=2` `1N` of `H_(2)O_(2)=1.7%` of `H_(2)O_(2)` `2N` of `H_(2)O_(2)=3.4% H_(2)O_(2)` |
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