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A `5.2` molal aqueous of methyl alcohol, `CH_(3)OH`, is supplied. What is the molefraction of methyl alcohol in the solution ?A. `0.086`B. `0.050`C. `0.100`D. `0.190` |
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Answer» Correct Answer - A `5.2 m CH_(3)OH` ie 5.2 mol `CH_(3)OH` present in 1 kg water `X_(M) = (5.2)/(5.2 + (1000)/(18)) = (5.2)/(5.2 + 55.5) = (5.2)/(60.7) = 086` |
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