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Find number of `Na^(+)` & `PO_(4)^(-3)` ions in `250mol` of `0.2M Na_(3)PO_(4)` solution .

Answer» `Na_(3)PO_(4) + aq. Rarr 3 Na^(+) (aq) + PO_(4)^(-3)` (aq) [Ionic compound when added to water ionize compleltely]
50 millimoles (m.m) 150 mm 50 mm
No. of `Na^(+) " ions " = 150 xx 10^(-3) xx N_(A)` , No. of `PO_(4)^(-3) " ions " 50 xx 10^(-3) xx N_(A)`


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