A 5 m long aluminium wire `(Y=7xx10^10(N)/(m^2))` of diameter 3 mm supprts a 40 kg mass. In order to have the same elongation in a copper wire `(Y=12xx10^10(N)/(m^2))` of the same length under the same weight, the diameter should now, in mmA. 1.75B. 1.5C. 2.5D. `5.0`

A 5 m long aluminium wire `(Y=7xx10^10(N)/(m^2))` of diameter 3 mm sup

1.	A 5 m long aluminium wire `(Y=7xx10^10(N)/(m^2))` of diameter 3 mm supprts a 40 kg mass. In order to have the same elongation in a copper wire `(Y=12xx10^10(N)/(m^2))` of the same length under the same weight, the diameter should now, in mmA. 1.75B. 1.5C. 2.5D. `5.0`
Answer» Correct Answer - C

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A 5 m long aluminium wire `(Y=7xx10^10(N)/(m^2))` of diameter 3 mm supprts a 40 kg mass. In order to have the same elongation in a copper wire `(Y=12xx10^10(N)/(m^2))` of the same length under the same weight, the diameter should now, in mmA. 1.75B. 1.5C. 2.5D. `5.0`

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