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A 5 metre long wire is fixed to the ceiling. A weight of `10kg` is hung at the lower end and is `1metre` above the floor. The wire was elongated by `1mm`. The energy stored in the wire duw to streching isA. 0.01JB. 0.05 JC. 0.02 JD. 0.04J |
Answer» Correct Answer - B (b) The energy stored in the wire. `U=(1)/(2) xx F xx l=(1)/(2)mgl=(1)/(2)xx10xx10xx1xx10^(-3)=0.05 J` |
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