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A `50 Hz AC` source of `20 V` is connected across `R ` and `C` as shown in figureure. The voltage across `R` is `12 V`. The voltage across `C` isA. 8 VB. 16 VC. 10 VD. not possible to determine unless values of R and C are given |
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Answer» Correct Answer - B `V_("source")=sqrt(V_(R)^(2)-V_(C)^(2))` `:. V_(C)=sqrt(V_("Source")^(2)+V_(C)^(2))` `" " sqrt((20)^(2)-(12)^(2))=16V` |
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