Saved Bookmarks
| 1. |
A `50 Hz` alternating current of peak value `1` ampere flows through the primary coil of a transformer. If the mutual inductance between the primary secondary be `1.5` henry, then the peak value of the induced voltage isA. `75 V`B. `150 V`C. `100 V`D. None of these |
|
Answer» Correct Answer - c `di= 2-(1-1)=2A` `dt=((1)/(100))` `M=0.05H` `e=M(di)/(dt)= 0.5((2)/(1//100))` `=0.5xx2xx100` `=100V` |
|