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A 50 ohm lossless transmission line has a pure reactance of (j100) ohms as its load. The VSWR in the line is (a) 1/2 (b)2 (c) 4 (d)(infinity) |
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Answer» Correct option (d)(infinity) Explanation: Reflection coefficient Γ = (zL - z0)/(zL + z0) = (j100 - 50)/(j100 + 50) Γ = √(1002 + 502)/√(1002 + 502) = 1 VSWR = (1 + |Γ|)/(1 - |Γ|) = (1 + 1)/(1 - 1) = 2/0 = ∞ |
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