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A 500 kg satellite is in a circular orbit at an altitude of 500 km above the earth.s surface. Because of air friction, the satellite eventually falls to the Earth.s surface, where is hit the ground with a speed of 2km/s The work done by air friction is [M_(E ) = 6 xx 10^(24) kg, R_(E) = 6400 km] |
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Answer» `1.67 xx 10^(11)` J |
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