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A 500kg rocket is set for verticle firing. The exhaust speed is 800`ms^-2` . To give an initial upward acceleration of 20`ms^-2` , the amount of gas ejected per second to supply the needed thrust will be (g=10 `ms^-2` )A. `127.5 kg//s`B. `187.5 kg//s`C. `85 kg//s`D. `137.5 kg//s` |
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Answer» Correct Answer - B `Ma = v_(r ) (dm)/(dt)` `v_( r) (dM)/(dt) = M(a + g)` `(800) (dM)/(dt) = 5000 (20 + 10)` `(dM)/(dt) = 187.5 kg//s` |
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