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A 5m aluminium wire `(Y = 7 xx 10^(10) Nm^(-2)`) of diameter 3 mm supports a 40 kg mass. In order to have the same elongation in a copper wire `(Y = 12 xx 10^(10) Nm^(-2)`) of the same length under the same weight, the diameter (in mm) should beA. 1.75B. 1.5C. 2.3D. 5 |
Answer» Correct Answer - c `I = (FL)/(pi r^(2) Y) implies r^(2) prop (1)/(Y)` (F,L and I are constants) `(r_(2))/(r_(1)) = [(Y_(1))/(Y_(2))]^(1//2) = [(7 xx 10^(10))/(12 xx 10^(10))]^(1//2)` `implies r_(2) = 1.5 xx ((7)/(12))^(1//2) = 1.145 mm` `:.` Diameter = 2.29 mm. |
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