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1. |
A `6.90 M` solution of `KOH` contains 30% by weight of `KOH`. Calculate the density of the solution. |
Answer» `M = (% "by weighy" xx 10 xx d)/(Mw_(2))` `6.9 = (30 xx 10 xx d)/(56)` `d = 1.288 g mL^(-1)` |
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