1.

A 600 W mercury lamp emits monochromatic radiation of wavelength 313.3 nm. How many photons are emitted from the lamp per second ? (h = 6.626 xx 10^(-34) Js, velocity of light = 3xx 10^(8) ms^(-1))

Answer»

`1 xx 10^(19)`
`1 xx 10^(20)`
`1 xx 10^(21)`
`1 xx 10^(23)`

SOLUTION :`600 W = 600 J s^(-1) (1 W = 1 Js^(-1))`
i.e., Energy EMITTED per SEC = 600 J
Energy of one photon, `E = hv = h (C)/(lamda)`
`= (6.626 xx 10^(-34) Js xx 3 xx 10^(8) MS^(-1))/(313.3 xx 10^(-9) m)`
`= 6.344 xx 10^(-19) J`
`:.` Photons emitted per sec `= (600)/(6.344 xx 10^(-19))`
`~= 1 xx 10^(21)`


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