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A 600 W mercury lamp emits monochromatic radiation of wavelength 313.3 nm. How many photons are emitted from the lamp per second ? (`h = 6.626 xx 10^(-34) Js`, velocity of light `= 3xx 10^(8) ms^(-1)`)A. `1 xx 10^(19)`B. `1 xx 10^(20)`C. `1 xx 10^(21)`D. `1 xx 10^(23)` |
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Answer» Correct Answer - C `600 W = 600 J s^(-1) (1 W = 1 Js^(-1))` i.e., Energy emitted per sec = 600 J Energy of one photon, `E = hv = h (c)/(lamda)` `= (6.626 xx 10^(-34) Js xx 3 xx 10^(8) ms^(-1))/(313.3 xx 10^(-9) m)` `= 6.344 xx 10^(-19) J` `:.` Photons emitted per sec `= (600)/(6.344 xx 10^(-19))` `~= 1 xx 10^(21)` |
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