A `+6muC` point charge is moving at a constant velocity of `8xx10^6 ms^-1` in the +y direction, relative to a reference frame. At the instant when the point charge is at the origin of this reference frame, what is the magnetic field vector it produces at the following points? (a) `x=0.500m, y=0, z=0,` and (b) `x=0, y=-0.500m, z=0`.

A `+6muC` point charge is moving at a constant velocity of `8xx10^6 ms

1.	A `+6muC` point charge is moving at a constant velocity of `8xx10^6 ms^-1` in the +y direction, relative to a reference frame. At the instant when the point charge is at the origin of this reference frame, what is the magnetic field vector it produces at the following points? (a) `x=0.500m, y=0, z=0,` and (b) `x=0, y=-0.500m, z=0`.
Answer» For a charge with velocity `vecv=(8.00xx10^-6m//s)hatj`, the magnetic field produced at a position away from the particle is `vecB=(mu_0)/(4pi) (qvecvxxhatr)/(r^2)`. (a) `vecr=(+0.500m)hati implies hatvxxhatr=-hatk, r_0^2=1/4` `vecB=-(mu_0)/(4pi) (qv)/(r_0^2) hatk` `=-(mu_0)/(4pi) ((6.0xx10^-6C)(8.0xx10^6m//s))/((0.50m)^2)` `=-(1.92xx10^-5T)hatk` (b) `vecr=(-0.500m)hatj implies hatvxxhatr=0 implies vecB=0`

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