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    				| 1. | Two protons move parallel to each other with an equal velocity `v=300kms^-1`. Find the ratio of forces of magnetic and electric interaction of the protons. | 
| Answer» Correct Answer - `1.00xx10^-6` The force of magnetic induction is given by `vecF_(mag)=e(vecvxxvecB) Here vecB=(mu_0)/(4pi) (e(vecvxxvecr))/(r^3)` `:. vecF_(mag)=(mu_0)/(4pi)xx(e^2)/(r^3)[vecvxx(vecvxxvecr)]` `=(mu_0)/(4pi)xx(e^2)/(r^3)[(vecv.vecr)xxvecv-(vecv.vecv)xxvecr]` `=(mu_0)/(4pi)xx(e^2)/(r^3)xx(-v^2vecr)` `vecF_("ele.")=evecE=e 1/(4piepsilon_0) (evecr)/(r^3)` `:. |F_(mag)|/|F_("ele.")|=v^2mu_0epsilon_0=(v/c)^2=1.00xx10^-6` | |