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A `6V` battery of negligible internal resistance is connected across a uniform wire of length `1m`. The positive terminal of another battery of emf `4V` and internal resistance `1Omega` is joined to the point `A` as shown in figure. The ammeter shows zero deflection when the jockey touches the wire at the point `C`. The `AC` is equal to A. `2//3 m`B. `1//3 m`C. `3//5 m`D. `1//2m` |
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Answer» Correct Answer - A `x=6/1 v//m implies 6xxl_(AC)=4` `l_(AC)=2/3m` |
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