A 75kg man stands in a lift. What force does the floor exert on him when the elevator starts moving upward with an acceleration of 2 ms^(-2) Given: g = 10 ms^(-2).

A 75kg man stands in a lift. What force does the floor exert on him wh

1.	A 75kg man stands in a lift. What force does the floor exert on him when the elevator starts moving upward with an acceleration of 2 ms^(-2) Given: g = 10 ms^(-2).
Answer» Solution :R-mg =ma , R= mg + ma = m(g+a) `=75(10 + 2) N = 900N` ` =(900)/(10)` kg wt. = 90 kg. wt