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A 75kg man stands in a lift. What force does the floor exert on him when the elevator starts moving upward with an acceleration of 2ms^(-2) Given : g=10 ms^(-2). |
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Answer» SOLUTION :`R-mg = ma`, `R=mg+ma=m(g+a)` `=75(10+2)N=900N` `=(900)/(10)` kg wt. = 90 kg. wt |
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