1.

A 75kg man stands in a lift. What force does the floor exert on him when the elevator starts moving upward with an acceleration of 2ms^(-2) Given : g=10 ms^(-2).

Answer»

SOLUTION :`R-mg = ma`,
`R=mg+ma=m(g+a)`
`=75(10+2)N=900N`
`=(900)/(10)` kg wt. = 90 kg. wt


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