A 75kg man stands in a lift . What force does the floor exert on him when the elevator starts moving upward with an acceleration of 2ms^(-2) Given : g=10ms^(-2).

A 75kg man stands in a lift . What force does the floor exert on him w

1.	A 75kg man stands in a lift . What force does the floor exert on him when the elevator starts moving upward with an acceleration of 2ms^(-2) Given : g=10ms^(-2).
Answer» Solution :`R-mg=ma, R=mg+ma=m(g+a)` `=75(10+2)N=900N` `=(900)/(10) KG wt.=90kg .wt.`