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A 9 cm solid metallic cube and a solid metallic cuboid having dimensions 5 cm, 13 cm, 31 cm are melted and recast into a single cube. What is the total surface area (in cm2) of the new cube?1. 13622. 8653. 27444. 1176 |
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Answer» Correct Answer - Option 4 : 1176 Given: Side of cube = 9 cm Cuboid Dimensions Length = 5 cm, breadth = 13 cm, height = 31 cm Formula used: Volume of cube = (side)3 Volume of cuboid = length × breadth × height Total surface area of cube = 6 × side2 Calculation: Volume of Solid metallic cube ⇒ 93 ⇒ 729 cm3 Volume of Solid metallic cuboid ⇒ 5 × 13 × 31 ⇒ 2015 cm3 Volume of Recast single cube ⇒ Volume of Solid metallic cube + Volume of Solid metallic cuboid ⇒ 729 + 2015 ⇒ 2744 cm3 Side of Recast cube ⇒ (Side)3 = 2744 ⇒ side = 14 cm Total surface area of cube ⇒ 6 × 14 × 14 ⇒ 1176 cm2 ∴ The total surface area of recast cube is 1176 cm2. |
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