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(a) A current of 1.50 amp was passed through an electrolytic cell containing AgNO_3 solution with inert electrodes. The weight of Ag deposited was 1.50 g. How long did the current flow ? (b) Write the reactions taking place at the anode and cathode in the above cell. (c) Give reactions taking place at the two electrodes if these are made up of Ag. |
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Answer» Solution :(a) `I = 1.50 A, m = 1.50 g` ATOMIC MASS of Ag = 108 Eq. of mass of Ag = 108 108 g silver is deposited by = 96500 C 1.5 g silver is deposited by `=96500/108 xx 1.5 = 1340.28` C Quantity of electricity Q = `l xx t` or `t = Q/l` SUBSTITUTING the values, we get `t = (1340.28)/1.5 = 893.52 s` (b) At cathode: `Ag^(+) + e^(-) to Ag(s)` At anode: `2H_(2)O to 4H^(+) + O_(2) + 4e^(-)` ( c) At anode: `Ag^(+) + e^(-) to Ag(s)` At anode: `Ag to Ag^(+) + e^(-)` |
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