(a) A steel tank has internal volume V_0 (= 100 litre). It contains half water( volume = (V_0)/2 )and half kerosene oil at temperature theta_(1) = 10^(@)C Calculate the mass of kerosene that flows out of the tank at temperature of theta_(2)=40^(@)C. Coefficient of cubical expansion for different substances are: gamma_(k)=10^(-3).^(@)C^(-1), gamma_(w)=2xx10^(-4) .^(@)C^(-1), gamma_("steel")=1.2xx10^(-5).^(@)C^(-1). density of kerosene at 10^(@)C is rho_(1)=0.8 kg /litre. (b) In the last problem the height of water in the container at theta_(1)=10^(@)C is H_1 = 1.0 m. Find the height of water at theta_(2) = 40^(@)C.

(a) A steel tank has internal volume V_0 (= 100 litre). It contains ha

1.	(a) A steel tank has internal volume V_0 (= 100 litre). It contains half water( volume = (V_0)/2 )and half kerosene oil at temperature theta_(1) = 10^(@)C Calculate the mass of kerosene that flows out of the tank at temperature of theta_(2)=40^(@)C. Coefficient of cubical expansion for different substances are: gamma_(k)=10^(-3).^(@)C^(-1), gamma_(w)=2xx10^(-4) .^(@)C^(-1), gamma_("steel")=1.2xx10^(-5).^(@)C^(-1). density of kerosene at 10^(@)C is rho_(1)=0.8 kg /litre. (b) In the last problem the height of water in the container at theta_(1)=10^(@)C is H_1 = 1.0 m. Find the height of water at theta_(2) = 40^(@)C.
Answer» Answer :`(a) Delta m =(V_(0) rho_(1))/2 ((gamma_(k)+gamma_(w)-2gamma_(s)))/((1+gamma_(k) Delta theta)) Delta theta`; =1.37 kg [where `Delta theta=theta_(2) -theta_(1)`] (b) `(H_(1)[1+gamma_(w)Delta theta])/([1+2/3gamma_(s)Delta theta]) =1.0057 m`