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A: A thread of length L is streatched by a force of 5N, its length increases by a and stretched by force of 6N its length increases by b, now if it is stretched by force of 11 N its length increases by (a + b -L). R: Increasing the length of elastic thread is proportional to its initial length. |
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Answer» Both are true and the reason is the correct explanation of the ASSERTION. `l = FC` `therefore ` For first case ` a = L +l` `therefore a = L + FC = L + 5 C ""…(1)` `therefore b = L + F.C = L + 6C""…(2)` For second case, `therefore b -a = L + 6C -L-5C` `therefore b -a =C` If increase in length is x due to force 11N then, `x = L +11C""[F=11x]...(3)` From EQUATION (1) and (2), `C = (a -L)/(5) and C = (b-L)/(6)` `therefore (a-L)/(5) = (b-L)/(6)` `therefore 6a - 6L = 5-5L` `therefore 6a 05b =L""...(4)` Putting value of equation (4) in equation (3), `x = 6a - 5b + 11( b-a) [because C = b -a]` `=6a - 5b +11b -11a` `x = 6b -5a` `therefore` Assertion is false and reason in true. |
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