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A and B are friends and A is 2 years older than B. A's father D is twice as old as A and B's age is twice as old as his sister C's age. The difference between D and C's age is 40 years. Find the age of A.1. 25 years2. 15 years3. 40 years4. 26 years |
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Answer» Correct Answer - Option 4 : 26 years Given: D – C = 40 years. Calculation: According to problem D – C = 40 ⇒ C = D – 40 ----1 B's age is twice as old as his sister C's age B = 2(D - 40) ----2 A is 2 years older than B A = 2(D - 40) + 2 ----3 D is twice as old as A D = 2A ----4 ⇒ D = 2(2(D - 40) + 2) ⇒ D = 4D -160 + 4 ⇒ 3D = 156 ⇒ D = 52 years From equation 4 ⇒ A = 52/2 = 26 ∴ Age of age is 26 years |
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