A and B are friends and A is older than B by 2 years. A's father D is

1.	A and B are friends and A is older than B by 2 years. A's father D is twice as old as A and B is twiceas his sister C. If the ages of D and C differ by 40 years, then find the ages of A and B.
Answer» Let the age of A = x age of B = x+2 since, A's father D is twice as old as ASo, age of D = 2×x = 2x and since B is twice as old as his sisterSo, age of C = age of B / 2 = (x+2)/2 The ages of D and C differ by 40yrs.thus age of D - age of C = 40 2x - [(x+2)/2] = 40 2x - (x+2)/2 = 404x/2 - (x+2)/2 = 40 (4x - x + 2)/2 = 40 3x+2/2 = 40 3x + 2 = 40 × 2 3x = 80 - 2 x = 78/3= 26 So, age of A = x = 26 age of B = x + 2 = 26 + 2 = 28

A and B are friends and A is older than B by 2 years. A's father D is twice as old as A and B is twiceas his sister C. If the ages of D and C differ by 40 years, then find the ages of A and B.

Answer»

Let the age of A = x

age of B = x+2

since, A's father D is twice as old as ASo, age of D = 2×x = 2x

and since B is twice as old as his sisterSo, age of C = age of B / 2 = (x+2)/2

The ages of D and C differ by 40yrs.thus

age of D - age of C = 40

2x - [(x+2)/2] = 40

2x - (x+2)/2 = 404x/2 - (x+2)/2 = 40

(4x - x + 2)/2 = 40

3x+2/2 = 40 3x + 2 = 40 × 2

3x = 80 - 2

x = 78/3= 26

So, age of A = x = 26

age of B = x + 2 = 26 + 2 = 28