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A and B are friends and B is 2 years youngerthan A. A's father D is twice as old as A andB is twice as his sister C. The age of D andC differ by 40 years. The ages of 'A' and 'B'are respectively(A) 26 yrs., 24 yrs. (B) 25 yrs., 23 yrs.(C) 30 yrs., 28 yrs. (D) of these |
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Answer» Solution By the given conditionA-B=2 (i)Now as D is twice of 'A'D's age = 2A yearsand B is twice of his sister CC's age = B/2 yearsSo D is older than C2A-(B/2)=40 = 4A-B=80 (ii)solve (i) and (ii) eq.A=26B= 24 |
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