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A and B are ideal gases, the molecular weights of A and B are in ratio of 1 : 4. The pressure of a gas mixture containing equal weights of A and B is p atm. What is the partial pressure (in atm) of B in the mixture?(a) \(\frac{p}{5}\)(b) \(\frac{p}{2}\)(c) \(\frac{p}{2.5}\)(d) \(\frac{3p}{4}\) |
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Answer» Answer is : (a) \(\frac{p}{5}\) MA = a and MB = 4a WA = wB = m(say) \(\chi_B=\frac{m/4a}{m/4a+m/a}\) \(=\frac{1}{5}=\frac{p}{5}\) |
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