InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A and B are two metals with threshold frequencies `1.8xx10^(14)Hz and 2.2xx10^(14)Hz`. Two identical photons of energy of 0.825 eV each are incident on them. Then photoelectrons are emitted in take `h=6.6xx10^(-34)J//s`A. B aloneB. A aloneC. neither A nor BD. Both A and B |
|
Answer» Correct Answer - B (b) : `phi_(0A)=(hv_(0))/(e)eV=((6.6xx10^(-34))xx(1.8xx10^(14)))/(1.6xx10^(-19))eV` =0.74eV `phi_(0B)=((6.6xx10^(-34))xx(2.2xx10^(14)))/(1.6xx10^(-19))eV=0.91eV` Since the incident energy 0.825 eV is greater than 0.74 eV and less than 0.91 eV, so photoelectrone are emitted from metal A only. |
|