InterviewSolution
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InterviewSolution
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A photon of wavelength `6630 Å` is incident on a totally reflecting surface . The momentum delivered by the photon is equal toA. `6.63 xx 10^(-27) kg - m//sec`B. `2 xx 10^(-27) kg - m//sec`C. `10^(-27) kg - m//sec`D. None of these |
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Answer» Correct Answer - B The momentum of the incident radiation is given as `p = (h)/(lambda)`. When the light is totally reflected normal to the surface the direction of the ray is reversed . That means it reverses the direction of its momentum without changing its magnitude `:. Delta p = 2 p = ( 2h)/(lambda) = ( 2 xx 6.6 xx 10^(-34))/(6630 xx 10^(-10))` ` = 2 xx 10^(-27) kg - m // sec`. |
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