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| 1. |
a and b are two sides adjacent to the right angle of a right-angled triangle and p is the perpendicular drawn to the hypotenuse from the opposite vertex. Then $p^{2}$ is equal to1). $a^{2}+b^{2}$2). $\frac{1}{a^{2}}+\frac{1}{b^{2}}$3). $\frac{a^{2}b^{2}}{a^{2}+b^{2}}$4). $a^{2}-b^{2}$ |
| Answer» RIGHT ANSWER for this question is $\frac{1}{a^{2}}+\frac{1}{b^{2}}$ | |