A and B can do a piece of work in 25 days. B alone can do \(66 \frac{

1.	A and B can do a piece of work in 25 days. B alone can do \(66 \frac{2}{3}\)% of the same work in 30 days. In how many days can A alone do (4/15) part of same work?1. 122. 183. 204. 15
Answer» Correct Answer - Option 4 : 15 Given: Days taken by A and B together to do total work = 25 days Days taken by B to do \(66\frac{2}{3}\)% of total work = 30 days Formula used: No of days taken = (Total work)/(Efficiency) Calculation: Days taken by B to do (\(66\frac{2}{3}\)% = 2/3) of total work = 30 ⇒ Days taken by B to do total work = 30 × 3/2 = 45 days Total work = LCM of (30, 45) = 225 The efficiency of A and B together = 225/25 = 9 The efficiency of B = 225/45 = 5 The efficiency of A = 9 – 5 = 4 Days taken by A to do (4/15) part of total work = (225/4) × (4/15) = 15 days ∴ Time taken by A to do (4/15) part of the total work is 15 days

A and B can do a piece of work in 25 days. B alone can do \(66 \frac{2}{3}\)% of the same work in 30 days. In how many days can A alone do (4/15) part of same work?1. 122. 183. 204. 15

Answer» Correct Answer - Option 4 : 15

Given:

Days taken by A and B together to do total work = 25 days

Days taken by B to do \(66\frac{2}{3}\)% of total work = 30 days

Formula used:

No of days taken = (Total work)/(Efficiency)

Calculation:

Days taken by B to do (\(66\frac{2}{3}\)% = 2/3) of total work = 30

⇒ Days taken by B to do total work = 30 × 3/2 = 45 days

Total work = LCM of (30, 45) = 225

The efficiency of A and B together = 225/25 = 9

The efficiency of B = 225/45 = 5

The efficiency of A = 9 – 5 = 4

Days taken by A to do (4/15) part of total work = (225/4) × (4/15) = 15 days

∴ Time taken by A to do (4/15) part of the total work is 15 days

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