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A And B Together Can Do A Piece Of Work In 30 Days. A Having Worked For 16 Days, B Finishes The Remaining Work Alone In 44 Days. In How Many Days Shall B Finish The Whole Work Alone ? |
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Answer» A's 1 day's WORK = x and B's 1 day's work = y So (A & B) 1 day work = 1/30 => x+y =1/30 => 30x + 30Y = 1 -------- (1) So 16x + 44y = 1 -------- (2) By Solving above TWO equations, x = 1/60 and y = 1/60 B's 1 day's work = 1/60 Hence, B ALONE shall finish the whole work in 60 days. A's 1 day's work = x and B's 1 day's work = y So (A & B) 1 day work = 1/30 => x+y =1/30 => 30x + 30y = 1 -------- (1) So 16x + 44y = 1 -------- (2) By Solving above two equations, x = 1/60 and y = 1/60 B's 1 day's work = 1/60 Hence, B alone shall finish the whole work in 60 days. |
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