1.

A And B Together Can Do A Piece Of Work In 30 Days. A Having Worked For 16 Days, B Finishes The Remaining Work Alone In 44 Days. In How Many Days Shall B Finish The Whole Work Alone ?

Answer»

A's 1 day's WORK = x 

and B's 1 day's work = y

So (A & B) 1 day work = 1/30 => x+y =1/30

=> 30x + 30Y = 1 -------- (1)

So 16x + 44y = 1 -------- (2)

By Solving above TWO equations,

x = 1/60 and y = 1/60

B's 1 day's work = 1/60

Hence, B ALONE shall finish the whole work in 60 days.

A's 1 day's work = x 

and B's 1 day's work = y

So (A & B) 1 day work = 1/30 => x+y =1/30

=> 30x + 30y = 1 -------- (1)

So 16x + 44y = 1 -------- (2)

By Solving above two equations,

x = 1/60 and y = 1/60

B's 1 day's work = 1/60

Hence, B alone shall finish the whole work in 60 days.



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