1.

(a) Answer the following questions : (i) Which elements of the first transition series has highest second ionisation enthalpy ? (ii) Whichelements of the first transition series has highest third ionisation enthalpy ? (iii) Which element of the first transitionseries has lowest enthalpy of atomisation? (b)Identify the metaland justify your answer. (i) CarbonylM(CO)_(5) (ii) MO_(3)F

Answer»

Solution :(i) Cu. This is because ELECTRONIC configuration of Cuis `3d^(10)4s^(1)`. After loss of 1st electron, it acquires stableconfiguration of `3d^(10) `. Hence, removal removal of 2nd electron is very difficult.
(ii) Zn.This is because`Zn= 3d^(10) 4s^(2)` and `Zn^(2+) = 3d^(10)` which is again fully filledand hence is very stable. Removal of 3rd electronrequires very high ENERGY.
(iii) Zn. This is because it hascompletely filled 3d subshell and no unpaired electron is availableformetallic bonding .
(b) (i) Following EAN rule
(ii) `overset(x-2)(MO_(3))F^(-1), x-6-1=0, x= +7, i.e., ` M is in OXIDATION state `+7` Mn shows an oxidationstate of `+7`.Hence, the compound is `MnO_(3)F`


Discussion

No Comment Found