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= A AU ) AL e बह g TEEL ey 41000(e 6 T(11001, 1040 'SHh w, 01९1४) 0३Q: - %] ५

Answer»

Inner radius of the bowl= 4cm

Height of the cylindrical bowl= 6-2 = 4 cm

Volume of the cylinder = pi*r^2*h

= 22/7 *4*4*4

= 200.96cm^3

Now.,,, The total soup that can be available for 70 bowls= 200.96*70 =14067.2cm^3



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