1.

a b+5 and a2 +b[A] 6[C] 1050. If41, then the value of ab isB] 8[D] 12

Answer»

Given,a = b + 5a - b = 5 a^2 + b^2 = 41

We know, (a - b)^2 = a^2 + b^2 - 2ab5*5 = 41 - 2ab2ab = 41 - 252ab = 16ab = 16/2 = 8

Value of ab = 8

(B) is correct option



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