1.

A, B and C are three biomolecules. The results of the tests performed on them are given below:A, B and C are respectively : (1) A = Glucose, B = Fructose, C = Albumin (2) A = Lactose, B = Fructose, C = Alanine (3) A = Lactose, B = Glucose, C = Alanine (4) A = Lactose, B = Glucose, C = Albumin

Answer»

Answer is (4)

Alanine does not show Biuret test because Biuret test is used for deduction of peptide linkage & alanine is amino acid.

Albumine is protein so have paptide linkage so it gives positive Biuret test.

Positive Barfoed test is shown by monosaccharide but not disaccharide.

Positive Molisch's test is shown by glucose.

Answer is (4)

Lactose, Glucose and Fructose give +ve motisch's test.

Glucose give +ve barfoed test and fructose give –ve barfoed test.

Albumin give the biuret test and alamine give –ve Biuret test.

So, the answer should be 2.



Discussion

No Comment Found

Related InterviewSolutions