1.

A, B and C are three complexes of chromium(III) with empirical formula H_(12)O_(6)CI_(3)Cr. All the three complexes have water and chloride ions as ligands. Complex A does not react with conc. H_(2)SO_(4), whereas, complexes B and Close 6.7% and 13.5% of their original weight respectively on treatment with concentrated H_(2)SO_(4). Identity A, B and

Answer»

SOLUTION :`A=[Cr(H_(2)O)_(6)]Cl_(3)overset(H_(2)SO_(4))to NO reaction`
(therefour All `H_(2)O` molecules are present in co-ordination sphere)
`B = [CrCl(H_(2)O)]CI_(2)H_(2)Ooverset(H_(2)SO_(4))to` one mol e of `H_(2)O` is lost Molecular WEIGHT of complex = 266.5` % loss = `(18)/(266.5)xx100=6.75%``C=[CrCI_(2)(H_(2)O)_(4)]Cl_(2)2H_(2)O_(4)]Cl_(2)2H_(2)Ooverset(H_(2))to 2mol ES` of `H_(2)O` is removedTherefour% loss in weight `= (2xx18)/(266.5)XX(100)=13.50%`


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