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A, B and C can alone complete a work in 15, 25 and 30 days respectively. A and B started the work and after some days A is replaced by C. Now the work is completed in a further of 6 4/11 days. How much of the total work did B did ? |
Answer» ` 4/11` X days, And the B and C for `6 4/11 = 70// 11` days. So `(1//15 + 1//25)XXX+(1//25+1//30) xx (70//11)=1` `(8//75)xx x + (7//15)=1` Solve, `x=5` days So, B worked for `(5 + 70// 11) = 125 // 11` days In `125//11` days, B did `(125//11)xx (1//25) = 5//11` FO WORK |
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