1.

A, B and C working together can do a piece of work in 8 hours. A alone can do it in 20 hours and B alone can do it in 24 hours. In how many hours will C alone do the same work?1. 30 hours2. 32 days3. 34 hours4. 35 hours5. 40 hours

Answer» Correct Answer - Option 1 : 30 hours

Given:

A can do a piece of work in 20 hours 

B can do same work in = 24 hours 

A, B, and C working together can do the same work in = 8 hours

Concept Used:

If a man can do a work in x hours then he will do 1/x part of the work in 1 hour.

Calculation:

Work done by A in 1 hour = 1/20

Work done in 1 hour = 1/24  hour

Work done by A, B, C together in 1 hour =18

We know that, 

Work done by C in 1 hour = work done A, B, and C in 1 hour-work done by A and B in 1 hour

 \(\frac{1}{8} - \left( {\frac{1}{{20}} + \frac{1}{{24}}} \right)\)

⇒ \(\frac{1}{8} - \frac{{11}}{{120}}\)

⇒ (15 - 11)/120    (by taking LCM for 8and 120 which is 120 

⇒ \(\frac{4}{{120}}\)

⇒ 1/30 

∴ C complete the work is 30 hours



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