a + b + c = 0 then a3 + b3 + c3 = ………………A) \(\frac{abc}{3

1.	a + b + c = 0 then a3 + b3 + c3 = ………………A) \(\frac{abc}{3}\)B) 3 abc C) ab+c D) \(\frac{ab}{c}\)
Answer» Correct option is B) 3 abc Correct option is (B) 3 abc Since, \(a^3+b^3+c^3\) - 3ab \(=(a+b+c)(a^2+b^2+c^2-bc-ca-ab)\) \(\therefore\) If a + b + c = 0, then \(a^3+b^3+c^3\) = 3 abc.

a + b + c = 0 then a3 + b3 + c3 = ………………A) \(\frac{abc}{3}\)B) 3 abc C) ab+c D) \(\frac{ab}{c}\)

Answer»

Correct option is B) 3 abc

Correct option is (B) 3 abc

Since, \(a^3+b^3+c^3\) - 3ab \(=(a+b+c)(a^2+b^2+c^2-bc-ca-ab)\)

\(\therefore\) If a + b + c = 0, then \(a^3+b^3+c^3\) = 3 abc.