InterviewSolution
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InterviewSolution
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a+b+c=9 and ab+bc+ca=23then a3+b3+c3-3abc= |
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Answer» It is given that, 1. a+b+c=9 2.ab+bc+ca=23 Do the square of equation( 1) we get.(a+b+c)^2 = 9^2.a^2+b^2+c^2 +2(ab+bc+ca)=81.a^2+b^2+c^2+ 2(23)=81a^2+b^2+c^2+46 =81 3. a^2+b+c=81_46=35Now, a^3+b^3+c^3_ 3abc= (a+b+c)[a^2+b^2+c^2_ (ab+bc+ ca)]=9[35_ 23]=9[12]=108Hope it helps you. I think the correct answer is 108.hope it help you |
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