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A, B, C are three mutually exclusive and exhaustive events associated with a random experiment. If P(B) = (3/2) P(A) and P(C) = (1/2) P(B), find P(A). |
Answer» Here, P(A) + P(B) + P(C) = 1 …(1) For mutually exclusive events A, B, and C, P(A and B) = P(B and C) = P(A and C) = 0 Given: P(B) = (3/2) P(A) and P(C) = (1/2) P(B) (1) => P(A) + (3/2) P(A) + (1/2) P(B) = 1 => P(A) + (3/2) P(A) + (1/2){(3/2) P(A)} = 1 => P(A) + (3/2) P(A) + (3/4) P(A) = 1 => 13/4 P(A) = 1 or P(A) = 4/13 |
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