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A,B,C, are three non-collinear points with position vector veca, vecb,vecc respectively. Given, P,Q, R are points on BC, CA and AB respectively such that: BP : PC =CQ :QA =AR: RB=1:2 Find the position vectors of the vertices of the triangle XYZ formed by the lines AP, BQ, CR. Hence show that the centroid of triangleABC is same as that of triangleXYZ

Answer»


Answer :`vecX =(veca + 4vecb + 2vecc)/7, VECY=(4veca + VECB + 4vecc)/7, VECZ = (2veca + vecb + 4vecc)/7`


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